help me , serious and urgent please!
i have an assignment of calculus and could not solve it. i am not a mathematics major so please help me out to solve this

Limit (CosX-1)/X
X->0

Use L'hospital's rule for inderteminate cases of 0/0 or infinity/infinity.

- http://en.wikipedia.org/wiki/L'Hopital's_rule

Below is the solution. The result is zero.

Expand cosx as

Cosx = 1-(x^2/2!)+(x^4/4!)-......................
then
lim (Cosx-1)/x = Lim -(x/2!) + (x^3/4!)-...............= 0
x->0 x->0

lim -(1-cosx)
= -------------
x->0 x



(-1) lim 1-cosx
= ------------
x-->0 x


= (-1) * 0

= 0